Series

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 //1-1/(2*3)+1/(3*4)......  
 //Downloaded from www.c4cprog.co.nr  
 #include<conio.h>  
 #include<math.h>  
 void main()  
 {  
 int i,n;  
 float sum=1;  
 clrscr();  
 printf("Enter The Value Of N :");  
 scanf("%d",&n);  
 for(i=2;i<=n;i++)  
 sum=sum+(1/(i*(i+1.0))*(pow(-1,(i+1))));  
 printf("\n\n\tSum = %f",sum);  
 getch();  
 }